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Exception

 
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hi,
I have been solving mock exams on javabeat site and facing with the understanding part.Here is one ,
What happens when the following code gets executed:
class TechnoSample {
public static void main(String[] args) {
double d1 = 1.0;
double d2 = 0.0;
byte b =1;
d1 = d1/d2;
b = (byte) d1;
System.out.print(b);
}}

(1) It results in the throwing of an ArithmeticExcepiton
(2) It results in the throwing of a DivedeByZeroException
(3) It displays the value 1.5
(4) It displays the value ���1
answer is 1.Explain?
thankyou
 
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Posts: 329
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None of the given answers is correct. Try to compile and run it.
 
Greenhorn
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The answer is -1. Can someone please explain.
 
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Hi Nishant,

Have a look at the Java Language Specification.
[ June 18, 2007: Message edited by: Manfred Klug ]
 
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