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about finally and return statement

 
Ranch Hand
Posts: 188
IntelliJ IDE MySQL Database Java
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public class Sub {
static int read (int i) {
try {
if (i<5) return 5/i ;
else return i*5 ;
} catch (ArithmeticException e) {
System.out.println ("ArithmeticException") ;
} finally {
System.out.println("Finally");
return i+100 ; // look here
}
}
public static void main (String [ ] args) {
System.out.println (read(4)) ;
System.out.println (read(10)) ;
}
}

Why does it give a compile time error if return i+100 is commented when one of the above return statements are going to be executed
 
Sheriff
Posts: 11343
Mac Safari Java
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Consider what happens if read is called with a parameter of zero.

We enter the try block and find that i is less than 5, so we try to return 5/i. But in evaluating 5/i, we throw an ArithmeticException (because we're dividing by zero). When the exception is thrown, the code in the try block stops executing, and -- without returning anything -- execution transfers to the catch block and then the finally block. At that point, the exception has been handled, but we're still in the method, which must return an int...

(See how nice this looks with Code Tags? )
 
Sudarshan Sreenivasan
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Posts: 188
IntelliJ IDE MySQL Database Java
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thanks alot .... got the point and nice tip !!
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