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unsigned right shift operator ">>>".

 
srinibash udayasingh
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Hi Ranchers

i am always confuse to solve " unsigned right shift operator ">>>". ".

can anyone explain with examples how it works.

Thanks
 
Mallik Avula
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Hi srinibash udayasingh ,
If the left-hand operand is positive, the result is the same as a right-hift
For example: 16 >> 2 = 4
Decimal 16 00000000000000000000000000010000
Right-shift 2 00000000000000000000000000010000
fill left 00000000000000000000000000000100
discard right 00000000000000000000000000000100 -> Decimal 4

If the left-hand operand is negative,
For example: -16 >>> 2 = 1,073,741,820
Decimal -16 11111111111111111111111111110000
>>> 2 11111111111111111111111111110000
fill left 0011111111111111111111111111110000
discard right 00111111111111111111111111111100 -> 1,073,741,820.

Hope it will help you.
 
Bert Bates
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remember this topic is valid for the 1.4 exam but it's NOT on the 5.0 exam.
 
marc weber
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The signed right shift operator (>>) shifts to the right while maintaining the sign. That means it fills in positions on the left with the same value as the "sign bit" (the leftmost bit before the shift). This has the effect of keeping positive values (with a sign bit of 0) positive by filling in with zeros, and keeping negative values (with a sign bit of 1) negative by filling in with ones.

The unsigned right shift operator (>>>) shits to the right without caring what the original sign was. It simply fills in positions on the left with zeros.

(Note Bert's post above.)
[ July 20, 2007: Message edited by: marc weber ]
 
Don't get me started about those stupid light bulbs.
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