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Doubt in for loop

 
Divya Gehlot
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Hi,
Can any one explain me why in below code I am not anle to print anything what wrong with the for loop as far I see there is no error in the loop then why its neither even going intgo the loop nor printing total.
 
Akhilesh Trivedi
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"total > 30" implies "0 > 30"
 
Deepak Jain
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Its starightforward isn't it
int total=0;
for (int i = 0, j = 10; total > 30; ++i, --j)
0>30 false and hence it does not enter the for loop and result is 0
Thanks
Deepak
 
Polishetty Raghavendra
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Here the Value of total never more than 0 so it's printing the value as '0'.

If the Block of statements excuted then the value for total will change.

Regards
Raghavendra
 
Raghavan Muthu
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Just check the condition in the for loop. It is false thats why the control did not get into the loop!
 
Bob Ruth
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The way I always think of "for loop" conditions (just because it helps me) think of the MIDDLE parameter as a while(this is true) thing!

Yours was while( total > 0 ) so, as long as total is greater than 30, the code will make a pass through the loop. Just above the loop, since you set total to 0 it starts OUT LESS THAN 30, so when you hit the for statement the first time, it is already false and you never take a pass in to the body of the for loop. You may have actually meant to do "total < 30" which would have the for loop going up from total = 0 to 29 which would be 30 trips through the body of the loop.
 
Divya Gehlot
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Thanks I got it
 
Samuel Molina
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Besides, as far as I know, you CAN'T mix initializations AND declarations in the init part of the For loop.
 
Anand Hariharan
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Originally posted by Samuel Molina:
Besides, as far as I know, you CAN'T mix initializations AND declarations in the init part of the For loop.


Welcome to Java Ranch, Samuel.

Just a note to say that you can indeed define new variables in the init part of the for loop, so long as they are all of the same type. In other words, you can have ONE valid statement in the init part.

Note that the OP indicated that she was having an unexpected outcome which suggests a runtime issue (implying she got her code to compile).

- Anand
 
Samuel Molina
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Wow, that makes sense...
Thanks. I'll study harder.
 
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