Doubt about char type

[Manishk Rai]

Hi All ,

Below line does compile and prints 5
.

 char ch='\65';
   System.out.println(ch);   
  

But the below does not compile

   char ch='\85';
        System.oot.println(ch);
 

Please explain with the reason .

Thanks in Advance

Manish

[Sanjeev Singh]

Manishk,
Initializing a character with the value which starts with \(escape sequence) implies that the numbers are Octal ,unless prefixed with 0x for hexadecimal, so non of the digits should exceed 7.