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Doubt about char type

 
Greenhorn
Posts: 21
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Hi All ,

Below line does compile and prints 5
.

But the below does not compile


Please explain with the reason .

Thanks in Advance

Manish
 
Ranch Hand
Posts: 381
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Manishk,
Initializing a character with the value which starts with \(escape sequence) implies that the numbers are Octal ,unless prefixed with 0x for hexadecimal, so non of the digits should exceed 7.
 
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