Doubt regarding using same Object Memory for some case

[Manoj Macwan]

I have read in the K&B book that:

bytes, shorts, ints, booleans & chars exhibit immutability upto this range :
Boolean
Byte
Character from \u0000 to \u007f (7f is 127 in decimal)
Short and Integer from -128 to 127

I have some doubt regarding same:
Integer i1 = 10;
Integer i2 = 10;
Integer i3 = new Integer(10);
Integer i4 = new Integer(10);

System.out.println("i1 == i2: " + (i1== i2) + " i3 == i4: " + (i3== i4));

It gives the o/p as: i1 == i2: true i3 == i4: false

Is it like that while creating the new Object using new keyword, the above mentioned rule is not applies.

Please help me to understand this issue.

Thanks in Advance.

[Keith Lynn]

Anytime you use the keyword new, you are creating a new object. With autoboxing, certain references will refer to an already existing object.

[Deepak Jain]

Integer i1 = 10;
Integer i2 = 10;
Integer i3 = new Integer(10);
Integer i4 = new Integer(10);
System.out.println("i1 == i2: " + (i1== i2) + " i3 == i4: " + (i3== i4));


Till 127 Java will cache the values and hence i1 and i2 will refere to same single Integer(10) object in heap. But when you do i3 = new Integer(10) you are telling the compiler to create a new integer object.
And hence in the above code i1 == i3 you get false instead of getting true.

Only during autoboxing as with i1 and i2 java will cache the values and make the references to point to same immutable 10 value.
Thanks
Deepak