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doubt in try catch finally

 
Greenhorn
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Hi All ,
code --
try{
int a=2/0;
}catch(Exception e){
e.printStackTrace();
}finally{
System.out.println("Exception");
}

After running this I get O/p:
Exception
Excetion Trace

Is this the way it shud work ,,
Acc to me first catch will be done and then finally block
But o/p is opposite to wat I m thinking .
Can anyone correct me If I m wrong
 
Ranch Hand
Posts: 558
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I don't think the order is correct.

Since you are using Exception it can catch its sub-class "Arithmeticexception"
So first catch block executes and finally there after.
 
Ranch Hand
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Hi,
I tried this and it runs as expected :

1 : execution of the catch block
2 : execution of the finally block

Here's my output :

java.lang.ArithmeticException: / by zero
at scjp.Main.main(Main.java:18)
Exception

Use your debugger to follow the code execution.
 
Ranch Hand
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Hi,

the problem here is that 'e.printStackTrace()' writes to standard error and ' System.out.println' to standard out. Dependent on the environment (e.g. Eclipse), the output from standard out and error may not be printed in the correct order.
 
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