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doubt in try catch finally

 
Greenhorn
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Hi All ,
code --
try{
int a=2/0;
}catch(Exception e){
e.printStackTrace();
}finally{
System.out.println("Exception");
}

After running this I get O/p:
Exception
Excetion Trace

Is this the way it shud work ,,
Acc to me first catch will be done and then finally block
But o/p is opposite to wat I m thinking .
Can anyone correct me If I m wrong
 
Ranch Hand
Posts: 558
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I don't think the order is correct.

Since you are using Exception it can catch its sub-class "Arithmeticexception"
So first catch block executes and finally there after.
 
Ranch Hand
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Hi,
I tried this and it runs as expected :

1 : execution of the catch block
2 : execution of the finally block

Here's my output :

java.lang.ArithmeticException: / by zero
at scjp.Main.main(Main.java:18)
Exception

Use your debugger to follow the code execution.
 
Ranch Hand
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Hi,

the problem here is that 'e.printStackTrace()' writes to standard error and ' System.out.println' to standard out. Dependent on the environment (e.g. Eclipse), the output from standard out and error may not be printed in the correct order.
 
Don't get me started about those stupid light bulbs.
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