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Formating with printf() and format()

 
Ranch Hand
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hi,

Can anyone explain me the code and the output



int i1 = -123;
int i2 = 12345;
System.out.printf(">%1$(7d< \n", i1);
System.out.printf(">%0,7d< \n", i2);
System.out.format(">%+-7d< \n", i2);
System.out.printf(">%2$b + %1$5d< \n", i1, false);
This produces:
> (123)<
>012,345<
>+12345 <
>false + -123<


Thanks in advance
 
Java Cowboy
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You can find the description of format strings in the API documentation for the class java.util.Formatter. That will explain exactly the output for those statements.
 
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The following article could be of interest.

System.out.printf() - J2SE5.0
 
Greenhorn
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In the first printf statement 1$ represents which argument to select from those given after a "," and ( represents that if the no. is -tive then it wll wrap it in "()".n 7 means it provides a space of 7 bits for it.d is used for integers...
In the second printf statement "0 and ," means it will insert 0's and ,'s in empty spaces that will remain after the digits.for instance here i2 is of 5 digits but we provide a space of 7 digits for it so this statement inserted a 0 and a , in blank spaces.
In the format statement "+-" represents that it will insert either + or - depending upon whether the no. is +tive or -tive.
In third printf statement "2$" means it will select the 2nd one and "b" is for boolean....
well it is explained in k&b you can check it from there.
best of luck.
 
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