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Strange question

 
Ranch Hand
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For the following code sample:

interface foo {
int k = 0;
}

public class test implements foo {
public static void main(String args[]) {
int i;
test t = new test();
i= t.k;
i= test.k;
i= foo.k;
}
}

What is the result?

A. Compilation succeeds.
B. An error at line 2 causes compilation to fail.
C. An error at line 9 causes compilation to fail.
D. An error at line 10 causes compilation to fail.
E. An error at line 11 causes compilation to fail.
Ans: A

Doubt: if I modify the code as
int i;
System.out.println(i);

test t = new test();
System.out.println(i);
i= t.k;

it gives compilation error �variable i might not have been initialized�.

Why is this so?

pls help
regards,
gitesh
 
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Posts: 99
Mac Eclipse IDE
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int i;
System.out.println(i);
...
it gives compilation error �variable i might not have been initialized�.

Why is this so?



You cannot use any local variable before initializing. But you can use instance variables without initializing because they are initialized by the default values.
 
Java Cowboy
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88
Android Scala IntelliJ IDE Spring Java
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Note: Please quote your sources
 
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Interface variables are implecitly
public static final
 
Gitesh Ramchandani
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thanks for help.

The source of question is unknown, i found it in some materials (txt file) i downloaded from net.
 
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