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byte range

 
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byte x=64;
byte y=5;
byte z= (byte)(x*y);

What is the value of z? The answer is 64, I am not getting how it is 64. I think if (x*y) goes out of byte range, output will be 0. Please can anyone explain?
 
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Hi,
I dont thnk it will be o. What ever bits are out of byte range would be ommited it seems.
 
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Dolly,

byte is only of 8 bits, so when x*y =320 is casted to byte, barring the leftmost 8 bits all are gone.

320 in binary =101000000
now
(byte)320 = 1000000 =64.

Regards,
Gitesh
 
dolly shah
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Thanks ,Gitesh, I got it
 
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