boxing method call doubt

[dolly shah]

public class Boxing9 {
    public static void main(String[] args) {
        int i = 10;
        method(i);
    }
    static void method(Object o){
        System.out.println("Object called");
    }
    static void method(Number n){
        System.out.println("Number called");
    }
}

What will be the output for the above program?
1)Object called
2)Number called-answer
3)Compiler Error
4)Runtim Exception


Why the answer is Number? I thought it is ambiguous between Object & Number. So the answer is compiler error.

[Keith Lynn]

No, it's not ambiguous.

The call matches both methods, but the one with parameter Number is more specific than the one with parameter Object. The most specific method that matches will be chosen in this case.

[dolly shah]

Thanks. I just forgot.

[Yogvinder Singh Ghotra]

Can someone explain this to me in detail??

[ahmed yehia]

Here the int literal 10 is first boxed to Integer which is then widened to Number.

[Jesper de Jong]

When two methods match the call, Java chooses the most specific method. See section 15.12.2.5 of the Java Language Specification. In this case, the method that takes a Number is more specific than the method that takes an Object.