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boxing

 
Ranch Hand
Posts: 50
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class A{
int doX(Long x,Long y){
return 1;
}
int doX(long...x){
return 2;
}
int doX(Integer x,Integer y){
return 3;
}
int doX(Number n,Number m){
return 4;
}
public static void main(String ar[]){
new A().go();
}
void go(){
short s = 7;
System.out.println(doX(s,s)+"");
System.out.println(doX(7,7));
}
}

short-->long-->Long //widing & boxing
short-->long...x //widing & boxing
short-->Short-->Integer//boxing & widing this is wrong
short-->Short-->Number //boxing & widing

int-->long--Long //widing & boxing
int-->long...x //widing & boxing
int-->Integer //boxing & widing //this is also correct
int-->Integer-->Number //boxing & widing // this is also correct


so how come the answer is 4,3
 
Greenhorn
Posts: 17
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hi
The answer 3 is right because
First it search for
1)primitive type then
2)Wapper classes then
3)varargs.
but i don't have idea for the O/P 4 and (on Number class)
 
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In the first invocation you pass two short primitives, first they are boxed to Short wrappers, now it has to find a match so it widen to Number as the only choice, here you cant widen to other type IS-A fails, Short cant become Integer.
In the second invocation you pass two int primitives which are simply boxed to Integers.
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