exception

[Hasitha Randika]

class A{
static int thrower() throws Exception{
return 43;
}
public static void main(String ar[]){
try{
int x= thrower();
}
catch(Exception e){
x++;//whats the error
}
finally{
System.out.prinln("x="+ ++x);//here allso
}
}
}
i thought the answer would be 44 but when i compile it gives a compile error? why's that

[Craig Bayley]

Hmmm...x is local variable within the try block, therefore catch and finally blocks can't access it?

[Jesper de Jong]

Craig's answer is correct: The variable x is declared inside the try-block, so its scope is limited to the try-block.

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