Inheritance

[Teo Framoe]

Why "Mum" in the 2. an 3. output line?
class Mom {
String s ="Mom";
void test() {
System.out.println(s);
}
void test2() {
System.out.println(s);
}
}

class Child extends Mom {
String s = "Child";
void test2() {
System.out.println(s);
}
}

class Test {
void test(Mom m) {
System.out.println("Mom");
}
void test(Child b) {
System.out.println("Child");
}

public static void main(String[] s) {
Test t = new Test();
Mom m = new Mom();
Child b = new Child();
Mom mb = new Child();

System.out.println("-Inherid-");
m.test(); //Mom
b.test(); //Mom Why1?
mb.test(); //Mom Why2?

System.out.println("-Overidden-");
m.test2(); //Mom
b.test2(); //Child
mb.test2(); //Child - Overridden : Runtrime

System.out.println("-Overloaded-");
t.test(m); //Mom
t.test(b); //Child
t.test(mb); //Mom - Overloaded : Compile time
}

}

[Pranav Bhatt]

Its because the test method is only in your Base class i.e Mom not in your Child one. So as cause of inheritance "mom" gets printed at both method calls as child have inherited those two methods.

Thanks
[ October 03, 2007: Message edited by: pranav bhatt ]

[Pankaja Shinde]

can anyone explain in detail

[vijaya bharath]

check this
https://coderanch.com/t/265549/java-programmer-SCJP/certification/Data-Hiding

[Srikanth Iyer]

That is because the method test is presnt only in your class mum and it gets inherited.....