Last week, we had the author of TDD for a Shopping Website LiveProject. Friday at 11am Ranch time, Steven Solomon will be hosting a live TDD session just for us. See for the agenda and registration link
Last week, we had the author of TDD for a Shopping Website LiveProject. Friday at 11am Ranch time, Steven Solomon will be hosting a live TDD session just for us. See for the agenda and registration link
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wrapper object

 
Greenhorn
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can you please explain the reason?

public class Test12{
public static void main(String a[]){
byte b = 100;
Byte b1= new Byte(100);
Byte b2 = new Byte(b);
System.out.println(b1 == b2);
System.out.println(b1.equals(b2));
}
}
What is output?

Answer:Complier error
 
Java Cowboy
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Try compiling it yourself. What error does the compiler give you exactly? Read the error message carefully and try to understand what it means.
 
Ranch Hand
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Byte b1= new Byte(100);
literals like 100 are of integer type by default.

To create a Byte object using new you should pass a byte

Try this
Byte b1= new Byte((byte)(100));
 
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