# i don't get it!.please somebody help me.

agustino felisberto

Greenhorn

Posts: 6

posted 8 years ago

why this code have this result

class Foozit {

public static void main(string[] arg {

Integer x = 0;

Integer y = 0;

for(Short z = 0;z < 5;z++)

if((++x> 2)|| (++y >2));

x++;

system.out.println(x + " " + y);

}

}

what was done?

can somebody explain me why the result is

the iteration loop?what was done?

**8 2**:class Foozit {

public static void main(string[] arg {

Integer x = 0;

Integer y = 0;

for(Short z = 0;z < 5;z++)

if((++x> 2)|| (++y >2));

x++;

system.out.println(x + " " + y);

}

}

what was done?

can somebody explain me why the result is

**8 2**the iteration loop?what was done?

Tony Smith

Ranch Hand

Posts: 229

posted 8 years ago

I haven't gone through it in detail, but take a look at :

if((++x> 2)|| (++y >2));

notice the || short-cut OR operator? that means if the left side is true, right side is never evaluated. So when ++x>2, it will never go to ++y>2 part, so that kind of explain why y is ended up with just 2. So go over the code few times and write in paper and see what happens.

if((++x> 2)|| (++y >2));

notice the || short-cut OR operator? that means if the left side is true, right side is never evaluated. So when ++x>2, it will never go to ++y>2 part, so that kind of explain why y is ended up with just 2. So go over the code few times and write in paper and see what happens.

agustino felisberto

Greenhorn

Posts: 6

posted 8 years ago

yeah.this where is exactly my problem the left side.the right side i fully understand. why the left side stops at

lets see x=0 y=0;

x=1 y=1;

x=2 y=2;

x=3 if((++x>2)|| {++y >2)) true. i think it stops there with the third iteration of the loop,y is never touched again.

my question is why x==8 at end?not 10 or 12?or even x==3 and y==2?this exercice is in the book scjp(kathy sierra& bert bates).

**8**?lets see x=0 y=0;

x=1 y=1;

x=2 y=2;

x=3 if((++x>2)|| {++y >2)) true. i think it stops there with the third iteration of the loop,y is never touched again.

my question is why x==8 at end?not 10 or 12?or even x==3 and y==2?this exercice is in the book scjp(kathy sierra& bert bates).

ronnir paterl

Greenhorn

Posts: 11

posted 8 years ago

its pretty simple...

Consider the outermost for loop

for z=2 x reaches 3

now apply x++ (because "if" condition is evaluated to be true by Short circuit evaluation)

so at this point z=2, x=4 and y=2

similarly when z=3, x=6 and y=2

and finally z=4, x=8 and y=2

the basic idea is once z reaches 2, x increments twice (++x and x++) for every value of z

Consider the outermost for loop

for z=2 x reaches 3

now apply x++ (because "if" condition is evaluated to be true by Short circuit evaluation)

so at this point z=2, x=4 and y=2

similarly when z=3, x=6 and y=2

and finally z=4, x=8 and y=2

the basic idea is once z reaches 2, x increments twice (++x and x++) for every value of z