Post Operator

[Akhil Maharaj]

Hi ,

In the following code how come the result is 7 ?

  static public void main(String...arg)
    {
        int i=1;
        int result = 5+i++%4*i;
       //int result = 7%8;
        System.out.println(result);
    }  

[Kelvin Chenhao Lim]

"i++" evaluates to the value of i before the increment. So here's how your expression gets evaluated step by step (parentheses added for clarity):

    5 + (((i++) % 4) * i)     (where i=1)
==> 5 + ((1 % 4) * i)         (where i=2)
==> 5 + (1 * i)               (where i=2)
==> 5 + (1 * 2)               (where i=2)
==> 5 + 2                     (where i=2)
==> 7

[ November 02, 2007: Message edited by: Kelvin Lim ]

[Akhil Maharaj]

Thanks

[Milton Ochoa]

Monster respose.

Thank you
[ February 26, 2008: Message edited by: Milton Ochoa ]