On Threads From Dan Chisholm's mock

[Vishwanath Krishnamurthi]

Hi friends,

In this code below why is it that B's run is not the one that's run? (and why its A instead)...

class A extends Thread {  
                                      
  public A(Runnable r) {super(r);}
  public void run() {System.out.print("A");}
}
class B implements Runnable {
  public void run() {System.out.print("B");}
}
class C {
  public static void main(String[] args) {
    new A(new B()).start();
}}
    

OUTPUT:
A
==============================

I thought the Runnable r=new B(); here and super(r) would become,
super(new B())
Does it happen so?

[Sergey Petunin]

First the start method invokes the run method of the Thread object, wich in turn invokes the run method of the Runnable constructor parameter.
Here the run method of the thread is overriden, so it doesn't start the Runnable's run method, only printing "A" instead.

[Vishwanath Krishnamurthi]

Read through your explanation over and over again and now I got that...
Thanks, Serge.