Moieen Khatri

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Posts: 144

posted 9 years ago

Hi,

Can someone explain the below question from K & B collections chapter:

Question:

I didn't understand this question and the solution explaination given below:

Please can someone explain this with an example?

Thanks

Can someone explain the below question from K & B collections chapter:

Question:

**Given a properly prepared String array containing five elements, which range of results could a**

proper invocation of Arrays.binarySearch() produce?

A. 0 through 4

B. 0 through 5

C. -1 through 4

D. -1 through 5

E. -5 through 4

F. -5 through 5

G. -6 through 4

H. -6 through 5proper invocation of Arrays.binarySearch() produce?

A. 0 through 4

B. 0 through 5

C. -1 through 4

D. -1 through 5

E. -5 through 4

F. -5 through 5

G. -6 through 4

H. -6 through 5

I didn't understand this question and the solution explaination given below:

**G is correct. If a match is found, binarySearch()will return the index of the element that**

was matched. If no match is found, binarySearch() will return a negative number that,

if inverted and then decremented, gives you the insertion point (array index) at which the

value searched on should be inserted into the array to maintain a proper sort.was matched. If no match is found, binarySearch() will return a negative number that,

if inverted and then decremented, gives you the insertion point (array index) at which the

value searched on should be inserted into the array to maintain a proper sort.

Please can someone explain this with an example?

Thanks

Serg Masow

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Posts: 50

posted 9 years ago

Hi Moieen,

assume you have a sorted array with five elements like this

int[] array = { 0, 2, 4, 6, 7 };

If you search for an element which is present in array for example 4

int result = Arrays.binarySearch(array, 4);

your result will be the index of the element in this array: 2.

If you search for an element, which is not in array, for example 5

the result is an negative number, which represents an insertion point of this element to keep the array sorted. Imagine you have to put 5 in this array so that array stay sorted. The new array would be { 0, 2, 4, 5, 6, 7 }. The position of 5 would be 3. The result of binarySearch() is the fictive position of 5 in the new array negated and decremented ( -3 - 1 = -4). The result of search is -4.

The maximum positive result of the binarySearch() is the biggest index of the array ( which is in this example 4 ) and the minimum insertion point is the fictive position after the element 7 which is -6. So the range of the search results is from -6 to 4.

Sorry for my poor English

assume you have a sorted array with five elements like this

int[] array = { 0, 2, 4, 6, 7 };

If you search for an element which is present in array for example 4

int result = Arrays.binarySearch(array, 4);

your result will be the index of the element in this array: 2.

If you search for an element, which is not in array, for example 5

the result is an negative number, which represents an insertion point of this element to keep the array sorted. Imagine you have to put 5 in this array so that array stay sorted. The new array would be { 0, 2, 4, 5, 6, 7 }. The position of 5 would be 3. The result of binarySearch() is the fictive position of 5 in the new array negated and decremented ( -3 - 1 = -4). The result of search is -4.

The maximum positive result of the binarySearch() is the biggest index of the array ( which is in this example 4 ) and the minimum insertion point is the fictive position after the element 7 which is -6. So the range of the search results is from -6 to 4.

Sorry for my poor English

SCJP 6.0 [95%] OCE EJBD 6.0 [93%]

Moieen Khatri

Ranch Hand

Posts: 144

Moieen Khatri

Ranch Hand

Posts: 144

Don't get me started about those stupid light bulbs. |