Problem wrapper value

[Prasun Howlader]

public class DemoTest{
public static void main(String[]args){
int i = Integer.MAX_VALUE + 1;
System.out.println(i);
}
}
This program run successfully.Why no error generated?

[sweta doshi]

Hello ,

Look at the output ...it gives you " -2147483648 " which means it goes back to the Integer.MIN_VALUE . And hence does not throw any error .

Thanks

[Prasun Howlader]

You could not understand my question?
compare with
int i = 2147483674 + 1
Now what happing?

[sweta doshi]

Hi ,

You are trying to say that it should normally add 1 to the highest value which should result in an error simply because it is no longer in the range of int.. right ?

Thanks

[sweta doshi]

Hi ,

int i= 2147483647 + 1;
If i use the above , it throws a compiler error saying that it is out of range since int cannot hold it . You already trying to stuff something into an int that is not appropriate for int. Rather use long . I hope this answers you .

Thanks

[Prasun Howlader]

Dear sweta doshi you again tell the same thing.

Look at my first post. here i use wrapper Integer.MAX_VALUE +1 and assign the value into the int variable. But in that case it generated no error why?

[Narendra shah]

Hi Dear. Which Compiler are you using. It do not throw any compiler error. I had tried with all 1.3,1.4,5,6. No errors in compilation or runtime.

[Deepak Jain]

Prasun as you mentioned in post you are trying to add 2147483674 and not 2147483647 to 1 and assign to i. Here 2147483674 is clearly out of range for int since its range is from -2147483648 to 2147483647
The below code compiles fine.

 int i1 = Integer.MAX_VALUE + 1;
 System.out.println(i1);
 int i3 = 2147483647 + 1;
 System.out.println(i3);

May you got confused with the MAx value.