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why the output is 0?

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For Line 1 follow this step-
1) Get value of i (0 for now for post increment), put it somewhere
2) increase the value of i (i value is 1 now)
3) assign the value stored somewhere(in this case 0) back to i (i value is 0 again)

For Line 2 follow above the procedure and the result is 0.

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hi..
this is very tricky question..here is the explanation..
first of all i++ or ++i is an atomic operation..

i++ or ++i both are equivalent to:

but how you use them..is much interesting..!!

j = i++ or ++i both are different..
suppose i = 0 at starting:

Now replace j with i

Abhijit Das
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hi , prasun,
explanation is Ok, but where the value 1 will be stored.

Greenhorn
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i= 0;

i = i++ is equivalent to the next 3 lines of code.

temp = 0;
i = i + 1; ie) i = 1 at this point of execution;
i = temp; ie) i = 0 again at this point of execution

So at the end of execution of i = i++, i has a value of 0.

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