instanceof

[Swati Kadam]

Integer ii = new Integer(10);
System.out.println(ii instanceof (Object));


The code does not compile....

System.out.println((ii) instanceof Object);
Now it compiles....
why is it so???

[Swati Kadam]

Got the answer..
The code does not compile. It is not allowed to surround the type with parenthesis. You can only surround the object

[marc weber]

Actually, I was surprised it compiles either way, but I see (ii) just evaluates to a reference.

It does not compile with the type (Object) in parenthesis, because this is an "illegal start of type."
[ March 11, 2008: Message edited by: marc weber ]

[Tim Weide]

Wow, who comes up with this stuff? I sure hope this kind of thing doesn't pop up on the exam.

Here's one for you. What does it do?

<_>_ _(_ _){return(_)_;}

[sridhar row]

swati can you please quote the source of your questions it will help..Thanks

[yu yong]

Integer ii = new Integer(10);
System.out.println(ii instanceof Object);

it compiles ~_~

[Ram Manoj]

Wow Tim,

<_>_ _(_ _){return(_)_;}

looks interesting.

But has compounded my fear of generics.
Generics scare me when wild cards are used.

[Madhukar Ojha]

You have to write like this .

if( ii instanceof Object ){
........
}
Parenthesis is not allowed .