Byte Data Type

[Sabber bhatia]

class BytePractice
{
public static void main(String[] args)
{
byte b1=33;
b1++;
byte b2=55;
b2=b1+1;
System.out.println("value of b1 and b2"+b1+ " "+b2);
}
}
Its givind=g compile time error
I do not understand why
see byte limit is -128 to 127 and here
b2=b1+1//means b2=33+1=34(which also comes under byte limit)
So what is the problem

why error ossible loss of precision

[Amit Ghorpade]

Hi,

see byte limit is -128 to 127 and here
b2=b1+1//means b2=33+1=34(which also comes under byte limit)
So what is the problem

it is correct that byte limit is -128 to 127 , but the + operator in b2=b1+1 is your problem, it works with int values
to get around it, just typecast the result into byte before assignment.
Remember here since you are might lose precision, you need an explicit cast
so you don't blame the compiler after implicit cast.


Hope this helps

[Sabber bhatia]

thanks amit