Formatter question

[Gabriela Rios]

In K & B at the end of chapter 6

    
 
int i1 = -123;
int i2 = 12345;
System.out.printf(">%1$(7d< \n", i1);
System.out.printf(">%0,7d< \n", i2);
System.out.format(">%+-7d< \n", i2);
System.out.printf(">%2$b + %1$5d< \n", i1, false);
 

Output

> (123)<
>012,345<
>+12345 <
>false + -123<

I don't understand why >012,345<. Could you tell me why the comma is in that position. By Default?? If I don't specified the precision. it uses 3?

[Daniel Del Moral]

It's a comma for grouping thousands, not decimals. That's might be confusing you. It's this kind of comma:

123,456.78 or
1,234,567.89
[ May 25, 2008: Message edited by: Daniel Del Moral ]

[Gabriela Rios]

Oh. You're right. Thank you.