help needed

[Kumar Gaurav]

public class ExceptionDemo2 {

public static int meth() {

try {
throw new RuntimeException("ExceptionGenerated");
}catch(Exception e) {

System.out.println("HELO hoo");
return 1;
}
finally {
System.out.println("HELO boo");
return 2;
}
}
public static void main(String[] args) {

int j=meth();
System.out.println(j);
}
}

Here i am not able to understand why return statement in catch block not getting executed.
Any help???

[ramesh maredu]

  catch(Exception e) {
 
System.out.println("HELO hoo");
return 1;
}
finally {
System.out.println("HELO boo");
return 2;
}  

Here once exception raises, it reaches catch block since you have return statement in catch block, it will go to finally and execute the code, but in finally you have return statement, so it will return from finally only, it will not return to catch again.

[chander shivdasani]

The point to remember is that, finally block will always be executed.

the return statement passes the control to finally block. Then the return statement in the finally block is executed.

The return statement in the catch block is executed, but the control is returned to finally, and then the finally block is executed. To clarify, you can remove the return statement in the finally block and then run the program.

And even quote the source for this question other wise your post will be deleted.

[Jesper de Jong]

Welcome to JavaRanch. When you post a question, please use a meaningful subject line instead of something like "help needed".