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shadowing local variable

 
Ranch Hand
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class JMM125 {
static int i;
public static void main(String args[]) {
for (i=1; i<3; i++) {System.out.print(i);} // 1
for (int i=1; i<3; i++) {System.out.print(i);} // 2
int i; // 3
for (i=0; i<2; i++) {System.out.print(i);} // 4
System.out.print(JMM125.i);
}}

output: 1212013
I am not getting how the 3 comes in while invoking (JMM125.i)?
what are all the things happening here with int i?
Please explain me this...
i am running out of this concept...

Preparing SCJP5
Thanks in advance
 
Sheriff
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the last 3 is from the statement

System.out.print(JMM125.i);

It was set to 3 by the first for loop...

All the three loops are using different i. The first loop uses the static i in class JMM125, the second one uses it's own local i, whose scope is inside the loop. The third loop uses i, which is local to main method...
[ October 12, 2008: Message edited by: Ankit Garg ]
 
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JMM125.i -> it is not all considering any of the local variablse. it deals with the class variable, i. since the value of i is used in the first for loop and incremented to 3, the value displayed would be 3.
 
Greenhorn
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Yeh coz the classname.variable name is used you are refering to the static variable declared globally.


[ October 13, 2008: Message edited by: Rajasekhar Devi Reddy ]
[ October 13, 2008: Message edited by: Rajasekhar Devi Reddy ]
 
Preethi Dev
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I got the concept works here...but the i value is supposed to be 2.How come it's getting 3?
 
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because in first loop i's final value was 3, since the condition was i<3, the control came out of the loop, though inside the first loop the i's value is 2, after the loop got over, the value was 3
 
Anoobkumar Padmanabhan
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Hi



This loop will terminate only when the condition, i<3 fails. ie, only when i==3. so the final value of i, after this loop will be 3.
 
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