How to generate a text file? Please Help

[Anonymous]

I have an application in which some text (that includes int and double values) to certain file. How can I view a text file.
I tried with RandomAccessFile by writing the text and numbers using WriteInt and WriteDouble methods etc. But when I tried to view the text file..it displays all the junk with some characters as *...and etc. Can any one please help me..
Neelima.

[Rahul Mahindrakar]

Try using the FileOutputStreams or the FileWriter class. An example of the FileOutputStream is given below.

import java.io.*;
class  demo3
{
public static void main(String[] args) throws Exception
{
FileOutputStream dd=new FileOutputStream("rahul");
dd.write('a');
dd.write('b');
dd.close();
System.out.println("Hello World!");
}
}

The RandomAccessFile methods too work but you may have to use the correct methods like this

import java.io.*;
class  demo3
{
public static void main(String[] args) throws Exception
{
RandomAccessFile dd=new RandomAccessFile("rahul","rw");
dd.write('a');// this works
dd.write('b');// this works
dd.write('1');// this works
dd.writeInt(2);// this doesn't work
dd.close();
System.out.println("Hello World!");
}
}

[This message has been edited by Rahul Mahindrakar (edited October 02, 2000).]

[Neelima Garimella]

Thank you Rahul,
I tried using FileOutputStream and RandomAccessFile as you have specified. I also tried the examples that you have given. But, it gives a compile time error as "Invalied character Constant", at the place of single quote. i.e., at the place of write('10').
Neelima

[Rahul Mahindrakar]

Neelima ,
the Write method is overloaded in many ways. Please check up the documentation for this. it takes a char, a char array etc..But it does not take a string. Please note that '10' is not a valid character but '1' and '0' are.

[srival vas]

continuing on this topic, how would I write a newline character
to a text file,
a character like 's', I can cast off to int and proceed but
I am stuck at a newline character.

[Rahul Mahindrakar]

Hope the code below will clarify things for you adequately

class demo1234 
{
public static void main(String[] args) 
{
char c='\n';
System.out.println("r" + c + "r");
}
}

[This message has been edited by Rahul Mahindrakar (edited October 15, 2000).]