Enjoy, pass a
string as the filepath, then get the contents of the file via getFileContent() which returns a stringbuffer. To create a string call
the toString() of the stringbuffer object. This code is really fast !!
[ August 20, 2002: Message edited by: Mark Nicholas ]
[ Edited by Dave to format code ]
[ August 20, 2002: Message edited by: David O'Meara ]