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Client does not run

 
Greenhorn
Posts: 7
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Hi, I am new at EJB and i read Head First EJB.I use Windows XP,J2EE Reference Implementation and J2SDK 1.4.2.When i tried to run the first example and specifically the client (AdviceClient) the following message was displayed:
E:\source\projects\advice>java AdviceClient
Context Created!!!
javax.naming.NoInitialContextException: Need to specify class name in environmen
t or system property, or as an applet parameter, or in an application resource f
ile: java.naming.factory.initial
at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:6
40)
at javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:243
)
at javax.naming.InitialContext.getURLOrDefaultInitCtx(InitialContext.jav
a:280)
at javax.naming.InitialContext.lookup(InitialContext.java:347)
at AdviceClient.go(AdviceClient.java:21)
at AdviceClient.main(AdviceClient.java:12)

---------------------------CODE---------------------------------------------
import javax.naming.*;
import java.rmi.*;
import javax.rmi.*;
import headfirst.*;
import javax.ejb.*;

public class AdviceClient
{
public static void main(String[] args)
{
new AdviceClient().go();
}
public void go() {
try
{
Context ic = new InitialContext();
System.out.println("Context Created!!!");
Object o = ic.lookup("Advisor");
System.out.println("Lookup DONE!!!");
AdviceHome home = (AdviceHome) PortableRemoteObject.narrow(o, AdviceHome.class);
System.out.println("Narrowing DONE!!!");
Advice advisor = home.create();
System.out.println("Remote Object Created!!!");
System.out.println(advisor.getAdvice());
}
catch (Exception ex)
{
ex.printStackTrace();
}
}
}

----------------------------------------------------------------------------
Now from the message i think that somewhere i must specify the properties of InitialContext.Am i right and if i am where and how can i do this? Kathy,Bert HELP please!
 
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