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replaceAll

 
Greenhorn
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I am trying to replace '*' with '%' in String


String value="*"
String str = value.replaceAll("*","%")
But I get a metadata error
 
Ranch Hand
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The first parameter for replaceAll is a String, but not a literal string, it is a regular expression.

The problem is that "*" has special meaning as part of an expression. To use a regular expression to match a single asterisk, use "\\*". The regular expression you want is '\*'. To get that you have to double the first backslash since "\*" is invalid -- it is not a valid Java escape sequence like "\n" or "\t". But "\\" means put in a single backslash. So if you code

String str = value.replaceAll("\\*","%");

it should work fine.

Dave Patterson
 
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Also, you can find more information on using regular expressions in Java here. If you don't know how to use regular expressions in general you should Google it.
 
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