i intend to convert a integer (or short or long) that is greater than a byte can hold (eg, 1111) to a byte array, since casting is simply cannot be used here, any other way can do it without lose precise? I have tried to use Integer wrapper class and use its toBinaryString() to convert the int to a string representation, eg 5->"101", then I really cannot find a way of converting "101" to a byte array with correct binary representation. Please help Give Me any Examples
(i >> 24) & 0xff is the high-order byte of i (i >> 16) & 0xff is the second byte of i (i >> 8) & 0xff is the third byte of i i & 0xff is the last byte of i
If you need to convert a bunch of data, consider using a DataOutputStream and a ByteArrayOutputStream in combination. The DataOutputStream's writeXXX() methods write the binary representation of Java primitive types, which would then be stored into the ByteArrayOutputStream.