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get fifth element from last linked list

 
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Hi,
Could anyone help me with a method for a Singly Linked List which gets fifth element from last linked list

I have the logic here:

1) have two ptrs. F_Ptr & S_Ptr.
2) Let the ptrs point to the START.
3) Take n as the offset.
4) Start traversing the S_Ptr after the F_Ptr after n.

suppose you want to find 5 element from the last of the list.

In the above case.

1) n = 5 // 5th element from the last
2) check atleast this many elements are there in the list before beginging


Thanks,
 
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Please do not post the same question more than once. It causes confusion and duplication of effort as the community tries to help everyone.
 
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