You may use these constants:

Parsec - 3.086E16 meters

C (velocity of light) - 3.0E8 meters/second

Sidereal Day - 86164 seconds

Your velocity may be stated as a percentage of the velocity of light and need not be more than three digits of accuracy for example: V = .578C or 57.8% C.

No warp speeds. 100% light speed is impossible, any value below that is acceptable.

*Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius - and a lot of courage - to move in the opposite direction.* - Ernst F. Schumacher

Originally posted by Anupam Sinha:

On a more serious note aren't they late.

Not sure what you mean here. Are you suggesting that within the constraints of velocity, that our good Commander can't get there in time?

*Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius - and a lot of courage - to move in the opposite direction.* - Ernst F. Schumacher

Originally posted by Anupam Sinha:

Sorry for the previous post. Didn't really get the question. I think that I still don't understand the question really but anyways my answer is 0.843C. I hope this is correct but think that this would be wrong.

Well, that's not the answer I got. So could you explain how you came up with that?

*Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius - and a lot of courage - to move in the opposite direction.* - Ernst F. Schumacher

187 Days till planet dissolves

2 days to prepare the device once it arrives

---

185 days travel time. (We can ignore the 77 days 'till the bomb is ineffective because we hope that the bomb is not ineffective).

185 days travel time * 86164 seconds = 15940340 seconds travel time

.13 parsecs = 4.0079 * 10^15 metres

Commander Gorlock must travel 4.0079 * 10^15 meters in 15940340 seconds, or he must travel at 251,431,274 meters/second.

C = 300, 000, 000

251,431,274 / 300,000,000 = .838104246667

So, Commander Gorlock arrives on site only to discover the planet is gone. He only took 185 days to travel, but (due to relativity), he took much longer than that to the outsiders. Or were you discounting relativity?

Piscis Babelis est parvus, flavus, et hiridicus, et est probabiliter insolitissima raritas in toto mundo.

Originally posted by Anupam Sinha:

I wasn't counting the 187th day. So I had :

distance=.13*3.086E16

time=184*86164

speed = distance/time

speed/3.0E8 = 0.843

[ July 01, 2003: Message edited by: Anupam Sinha ]

What about the volatility problem with the bomb?

What about the volatility problem with the bomb?

The bomb will be ineffective only after 77 days. So the captain has 184 or 185 days to reach and set up the bomb then leave. I guess that the volatility problem will not come into play as the bomb is being left for less than 77 days.

**So, Commander Gorlock arrives on site only to discover the planet is gone. He only took 185 days to travel, but (due to relativity), he took much longer than that to the outsiders. Or were you discounting relativity?**

Maybe I'm seeing it wrong? Relativity does count. I arrived at a solution. Let's let some others weigh in and see if I'm full of bovine excrement.

Sheriff

**What about the volatility problem with the bomb?**

What about it?

**The volatility of the bomb's components causes the bomb to be ineffective 77 sidereal days after assembly.**

If Gorlock doesn't start assembling the bomb until day 185, it doesn't really matter if the thing becomes inert 77 days later (or 79?) does it? It's done its job long before that.

Were you perhaps suggesting that the bomb components will become inert

*prior*to assembly, if more than 77 days have elapsed since they were taken from whatever safe storage they were in on Earth?

[ July 01, 2003: Message edited by: Jim Yingst ]

"I'm not back." - Bill Harding, *Twister*

**If Gorlock doesn't start assembling the bomb until day 185, it doesn't really matter if the thing becomes inert 77 days later (or 79?) does it? It's done its job long before that.**

I must not have been clear on that point. The bomb is assembled by experts on the space station

*before*Gorlock takes off. The constraints are he must make the journey to the planet within 185 days of the planets time frame and within 75 days of his time frame.

Sheriff

"I'm not back." - Bill Harding, *Twister*

Sheriff

**[Joel]: So, Commander Gorlock arrives on site only to discover the planet is gone. He only took 185 days to travel, but (due to relativity), he took much longer than that to the outsiders. Or were you discounting relativity?**

Relativity does indeed turn out to be important, but it's the other way around. The trip looks like it takes 185 days according to outside observers (the same guys who measure the distance to the planet as .13 parsecs) however the proper time on the ship is less. Proper time means the time as measured in a frame of reference that moves with the ship. In that frame, the ship isn't moving; everything else is. And the proper time tp is given by:

tp = t * sqrt( 1 - (v/c)^2 )

Using your values of t = 185 days and v = .8381 c we have

tp = 100.9 days

which means that unfortunately the bomb has gone inert. The means that a solution which meets the 185-day deadline is too slow - instead, forget that time and speed, and figure out how fast you need to go to get an elapsed proper time for the bomb of 75 days.

"I'm not back." - Bill Harding, *Twister*

Originally posted by Jim Yingst:

All right then, to make the trip in a subjective time of 75 days, a speed of .900 c is necessary. Round up a bit since a safety margin would be a good thing here, really. And it should be fun trying to accelerate to that speed in the first place (and decelerate later of course). I sure hope the ship has some of Star Trek's "inertial dampeners" (if not the warp drive) or the crew may end up as jello by the end of the trip.

Yup, I actually got .9004 c. Inertial dampers would be a plus, without 'em how do you drink your coffee on the commute?