# [Easy]Divide my uncle's estate!!

Arjun Shastry

Ranch Hand

Posts: 1899

1

posted 13 years ago

This was asked recently by one company during test:

When my Uncle in Bombay died recently ,he left a will, instructing his executors to divide his estate of Rs. 1,920,000 in this manner:

Every son should receive three times as a daughter,and that every daughter should get twice as much as their mother

What is my aunt's share?

When my Uncle in Bombay died recently ,he left a will, instructing his executors to divide his estate of Rs. 1,920,000 in this manner:

Every son should receive three times as a daughter,and that every daughter should get twice as much as their mother

What is my aunt's share?

MH

Timothy Chen Allen

Ranch Hand

Posts: 161

posted 13 years ago

Assuming that A is the number of sons and B is the number of daughters, and "s" is the son's share, "d" the daughter's, and "m" the mother's, the formula for the mother's share would derive as follows:

s = 3d // Son's share is 3 x daughter's

d = 2m // Mom's share is 2 x mother's

As + Bd + m = 1920000

A(6m) + B(2m) + m = 1920000

m = 1920000 / (6A + 2B + 1)

Here is a Java program to show all possible combinations between 0 and 9 sons and/or daughters (assuming only one mother!):

Originally posted by Capablanca Kepler:

When my Uncle in Bombay died recently ,he left a will, instructing his executors to divide his estate of Rs. 1,920,000 in this manner:

Every son should receive three times as a daughter,and that every daughter should get twice as much as their mother

What is my aunt's share?

Assuming that A is the number of sons and B is the number of daughters, and "s" is the son's share, "d" the daughter's, and "m" the mother's, the formula for the mother's share would derive as follows:

s = 3d // Son's share is 3 x daughter's

d = 2m // Mom's share is 2 x mother's

As + Bd + m = 1920000

A(6m) + B(2m) + m = 1920000

m = 1920000 / (6A + 2B + 1)

Here is a Java program to show all possible combinations between 0 and 9 sons and/or daughters (assuming only one mother!):