Originally posted by Jim Yingst:
Depends what "at each other" means. Were the canons aimed by someone who knows how to correct for gravity (and optionally, Coriolis forces)? Or did they just point "straight" at the other cannon and think that would work?
Originally posted by fred rosenberger:
more information than that is still needed. what if the velocity is barely enough to have the lower cannonball escape the muzzle? and the other cannon is 1 mile in the air? clearly, the ball from the lower cannon will hit the ground in about 1 second, while the other won't reach earth for a good minute or so...
Originally posted by HS Thomas:
Afterwards, consider Coriolis forces, if you please.
Jim Yingst : Well, pointing "straight" without bothering to take gravity into consideration, they'd miss, unless they're really close, because, well, gravity makes things fall.
Originally posted by David O'Meara:
Heh, trouble maker
Q: Two people holding swords stand on separate spinning tables (person spinning clockwise, B anti-clockwise) and make vertical chops at each other. Do they
C) Manage to rip their own arms off.
Though if the cannonball is big enough, and altitudes are similar enough, the trajectories may be close enough for the cannonballs to hit each other, despite being on differnet paths.
Assuming no external influences, if the balls were going to hit, it would be mid-way along the x axis.
Doody calls. I would really rather that it didn't. Comfort me wise and sterile tiny ad:
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