Finding all parameters in the request

[Dale DeMott]

I'm looking for a good way to iterate through all of the key, value pairs in the request. The key/value pairs that are in the request will be dynamic, so it can be anything. I do have a factory on the other side help me out w/this data once I get it, however I need to get this list first. Has anyone done this? Not sure how to attack this... Whats the best attack??

[Ben Souther]

 
    324
    325     //
    326     // Prints all form vars to the console.
    327     // For testing and debugging only
    328     //
    329     private void printFormVars(HttpServletRequest request){
    330         java.util.Enumeration enu = request.getParameterNames();
    331         while(enu.hasMoreElements()){
    332             String paramName = (String)enu.nextElement();
    333             log.debug("PARAM: "
    334                       + paramName
    335                       + ": "
    336                       + request.getParameter(paramName));
    337         }
    338     }
    339
 

I'm using log4j.
Just swap out the log.debug with System.out.println if you're not.

[Paul Bourdeaux]

Use request.getParameterNames(). It will return an Enumeration of Strings containing the names of all the request parameters. Then you can simply iterate through the Enumeration and get the value with request.getParameter().

[Paul Bourdeaux]

Ahh, Ben beat me to the answer. Oh well...

[Sharad Agarwal]

HttpServletRequest.getParameterNames?

[Ben Souther]

Originally posted by Sharad Agarwal:
HttpServletRequest.getParameterNames?

http://java.sun.com/j2ee/1.4/docs/api/javax/servlet/ServletRequest.html#getParameterNames()

[Sharad Agarwal]

I meant that as a pointer for the original poster. The answer was so obvious that I wasn't sure I understood his question properly, hence the '?' mark.

Later, I notice that you have already done his homework for him, and some

[Ben Souther]

Originally posted by Sharad Agarwal:

Later, I notice that you have already done his homework for him, and some

It was actually lazyness on my part. The file with the method was already open on my machine. It was easier to copy/paste the code into the browser than it would have been to type "getParameterNames"..

Judging from your previous posts, I was surprised to see the question mark.
Makes sense now.