My jdk path
C:\Program Files\Java\jdk1.5.0
My jsdk path
D:\JSDK2.0
My
Tomcat path
D:\Program Files\Apache Software Foundation\Tomcat 5.0
My HtmlFile path
E:\Programs\JSDK\DocRoot
contains: FirstServlet.html
My ServletFile path
E:\Programs\JSDK\Servlets
contains: FirstServlet.java and FirstServlet.class
Now how to execute my
servlet file?
This is my program
<HTML>
<HEAD>
<TITLE>
Test to invoke a Servlet </TITLE>
</HEAD>
<BODY>
<P> Invoking a Servlet from a Hyperlink </P>
<P> <A Href="http://localhost:8080/servlet/FirstServlet">
Click here to invoke a Servlet </A> </P>
</BODY>
</HTML>
servlet prog
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class FirstServlet extends HttpServlet
{
public void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException
{
PrintWriter out;
String title = "This is your first
Java Servlet Program";
//Set content type and other response header fields first
response.setContentType("text/html");
//Then write the data of the response
out = response.getWriter();
out.println("HTML");
out.println("<HEAD><TITLE>");
out.println(title);
out.println("</TITLE></HEAD>");
out.println("<BODY bgcolor=\"#FFFFFF\">");
out.println("<H2>Congratulations Ganesh!<BR>");
out.println("<H1>"+title+"</H1>");
out.println("</BODY>");
out.println("</HTML>");
//To close the Output stream
out.close();
}
}
plz guide me this is my first servlet program!
------------------------------------------
Thanks in Advance
Regards
Thanigaivel
[ October 08, 2005: Message edited by: S Thanigaivel ]