A question about Vectors

[kevin comario]

My question is can I create a multidimesional Vector as is possible with Arrays? Can I create a Vector of Vectors? The reason i ask is because I want to create a matrix that does not have an initial size.
Thank you for your help.

[Snigdha Solanki]

I guess so though I have never tried it. Are you getting any error?

[kevin comario]

Actually i dont know how to do it. I was hoping someone knew? That is why I was asking if its possible to do so. I'm kinda lost.

[Ta Ri Ki Sun]

sure you can, with no limit either, besides memory of course

 
Vector one = new Vector();
one.addElement(new Integer(1));
Vector two = new Vector();
two.addElement(one);
Vector three = new Vector();
three.addElement(two);

and so on
just remember that you're adding objects, so cast correctly when you get the objects back

[kevin comario]

sorry to bother you all again but. I am still a little confused. See what i want to do is create a matrix using vectors sort of like you do with multi-dimensional arrays. Like this:

for(int k = 0; k < 10; k++){
for(int i = 0; i < 10; i++){
matrix[k][i] = Integer.parseInt(st.nextToken());
}
}

but with vectors is there anyway of doing so.
If not thanks for the help anyway.

[Sarada Bhasker]

You will have to do something like this.

for(int k = 0; k < 10; k++){for(int i = 0; i < 10; i++){matrix[k][i] = Integer.parseInt(st.nextToken());}}

[Sabarish Sasidharan]

In a 2-dimensional array each element of the array is another array. Similarly each element of the Vector can be another Vector. Is that what you want ?

Vector parentVect = new Vector();
for (i = 1; i < n; i++) {
    parentVect.add(new Vector());
}

Now when u want to update for the first element

Vector firstVector = (Vector)parentVect.get(1);
firstVector.addElement(new Integer(1));
firstVector.addElement(new Integer(2));

Thus it can grow in both the dimensions indefinitely

[kevin comario]

Thank you Sabarish. I couldnt see it before now, i knew it was possible but was not sure how to do it. Once again thanks.