Parsing of script files in java

[Lewin Chan]

Hey,
The intermediate forum seems the best place to put this, as I'm sure someone can just point me to a URL where all this has been done.
Consider, a shell script (.bat/.cmd or unix style) that contains

JAR_DIR=/home/jar
APP_HOME=/home/lchan/app
JAR_LIB=$JAR_LIB:$JAR_DIR/log4j.jar
JAR_LIB=$JAR_LIB:$JAR_DIR/jdom.jar
JAR_LIB=$JAR_LIB:$JAR_DIR/lchan.jar
JAR_LIB=$JAR_LIB:$JAR_DIR/activation.jar
JAR_LIB=$JAR_LIB:$JAR_DIR/jakarta-oro-2.0.6.jar
JAR_LIB=$JAR_LIB:$APP_HOME/cfg
....
....
CLASSPATH=$APP_HOME:$JAR_LIB
....
....
java -classpath $CLASSPATH lchan.main

or, on windows

set JAR_DIR=c:\home\jar
set APP_HOME=c:\home\lchan\app
set JAR_LIB=%JAR_LIB%;%JAR_DIR%/log4j.jar
set JAR_LIB=%$JAR_LIB%;%JAR_DIR%/jdom.jar
set JAR_LIB=%JAR_LIB%;%APP_HOME%/cfg
....
....
set CLASSPATH=%APP_HOME%;%JAR_LIB%
....
....
java -classpath "%CLASSPATH%" lchan.main

How can I parse the file in java and resolve $CLASSPATH so that all the referenced variables are expanded.
At the moment, I've been able to get the "java -classpath" line out of the file, because lchan.main is the only real fixed reference point that I have...
Thanks in advance
L

[Cindy Glass]

Are you just trying to get the classpath of the machine, so that you know what it SHOULD resolve to?
You can use
String gotClassPath = System.getProperty(java.class.path);

[Lewin Chan]

Are you just trying to get the classpath of the machine, so that you know what it SHOULD resolve to?

Ultimately yes... However, this a class that is part of a separate jvm that has a different classpath from the one that would have been started by the script.