Boolean expression

[Robert Willems]

Hi,
we are reading the excellent book Java2 Study guide for 310-035 but we have a little question about a boolean expression that is in there.
it says that with the following statement:

  
if ((x > 3) && (y < 2) | doStuff()) {
  System.out.println( "true" ) ;
}

when y = 5, x = 2 and doStuff() always returns true, it will print nothing.
However in our mind it should evaluate to [BOLD]true[/BOLD]!
It says the runtime compiler would execute it like

  ((x > 3) && ((y > 2) | doStuff()))

Why??? Are there rules for the precedence of operators? Do the shortcircuit operator have a lower precedence than the boolean operators?
Have help would be appreciated.
Regards,
Robert Willems

[aminur rashid]

yes
bitwise inclusive OR '| '
is higher in precedence.
Check this
http://java.sun.com/docs/books/tutorial/java/nutsandbolts/expressions.html
Spec

[Robert Willems]

Thanks! that solves the whole problem ;-)