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How to programatically submit a html form?

 
Ranch Hand
Posts: 577
Tomcat Server Notepad Java
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Hi,

I have an HTML form. I have to write a java program wherein after getting some specific condition, I have to submit the HTML form without opening it in IE. How can I do this? Can someone show some light on this?

Thanks and Regards,
Narendranath
 
Greenhorn
Posts: 18
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if u don't want to open the HTML file in any browsers to submit ur form,
you can programatically sending a POST request using either a Socket or URL. The URL's example is look like:

try {
// Construct data
String data = URLEncoder.encode("key1", "UTF-8") + "=" + URLEncoder.encode("value1", "UTF-8");
data += "&" + URLEncoder.encode("key2", "UTF-8") + "=" + URLEncoder.encode("value2", "UTF-8");

// Send data
URL url = new URL("http://hostname:80/cgi");
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data);
wr.flush();

// Get the response
BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
// Process line...
}
wr.close();
rd.close();
} catch (Exception e) {
}
--------------------------------------
Using SOCKET:

try {
// Construct data
String data = URLEncoder.encode("key1", "UTF-8") + "=" + URLEncoder.encode("value1", "UTF-8");
data += "&" + URLEncoder.encode("key2", "UTF-8") + "=" + URLEncoder.encode("value2", "UTF-8");

// Create a socket to the host
String hostname = "hostname.com";
int port = 80;
InetAddress addr = InetAddress.getByName(hostname);
Socket socket = new Socket(addr, port);

// Send header
String path = "/servlet/SomeServlet";
BufferedWriter wr = new BufferedWriter(new OutputStreamWriter(socket.getOutputStream(), "UTF8"));
wr.write("POST "+path+" HTTP/1.0\r\n");
wr.write("Content-Length: "+data.length()+"\r\n");
wr.write("Content-Type: application/x-www-form-urlencoded\r\n");
wr.write("\r\n");

// Send data
wr.write(data);
wr.flush();

// Get response
BufferedReader rd = new BufferedReader(new InputStreamReader(socket.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
// Process line...
}
wr.close();
rd.close();
} catch (Exception e) {
}

u can find the additional information at http://javaalmanac.com
hope it helpful.
 
Naren Chivukula
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Posts: 577
Tomcat Server Notepad Java
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Thanks a lot. I'll try this. But which one is more optimistic?
 
author
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You can probably save a lot of work by using http://jakarta.apache.org/commons/httpclient/
 
You didn't tell me he was so big. Unlike this tiny ad:
Java file APIs (DOC, XLS, PDF, and many more)
https://products.aspose.com/total/java
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