unable to use throws clause inside run()

[siva sambo]

Hi friends, In the code below i want to remove the exception handling code (ie try-catch) and use throws clause. How do i do it??

import java.io.*;
 
public class ReverseThread extends Thread {
    private PrintWriter out = null;
    private BufferedReader in = null;
 
    public ReverseThread(PrintWriter out, BufferedReader in) {
        this.out = out;
        this.in = in;
    }
 
    public void run() {
        if (out != null && in != null) {
            try {
                String input;
                while ((input = in.readLine()) != null) {
                    out.println(reverseIt(input));
                    out.flush();
                }
                out.close();
            } catch (IOException e) {
                System.err.println("ReverseThread run: " + e);
            }
        }
    }
 
    private String reverseIt(String source) {
        int i, len = source.length();
        StringBuffer dest = new StringBuffer(len);
 
        for (i = (len - 1); i >= 0; i--)
            dest.append(source.charAt(i));
        return dest.toString();
    }
}
    

thanks in advance

[Keith Lynn]

You can't. If the superclass that you inherit the method from does not have the checked exception IOException or one of its superclasses in its throws clause, then you can't list the checked exception in the throws clause of the method when you override it.
[ February 24, 2006: Message edited by: Keith Lynn ]

[Jeff Albertson]

You are overriding a method (run) that throws no checked exceptions, so you can't throw IOException.

You need to think about how you want your code to behave. In high-level terms, what do you want to happen if an IOException occurs?