Two Constructers

[Shaan Shar]

Hello All,

I am writing a code which is giving an ambiguios solution the code is as follows:

public class Sample{
public static void main(String ar[]){
Sample sam = new Sample();
}
public Sample(){
System.out.println("In Simple Constructer");
}
public void Sample(){
System.out.println("In Void Type Constructer");
}
}

Now please suggest me what should be the output and also give me the reason.

[ak pillai]

Obviously it will print "In simple constructor"

If you have a rutun type like "void" then it is not a constructor anymore. it is a method with a duplicate name as the constructor.

[Arun Thakur]

ak pillai is right.

with the void its is no longer a constructer but a method which is returning nothing.

So it will print "In simple constructor"

[Arun Maalik]

Hey dear
It will print only that "In Simple Constructor". But well why see as long as U don't specify any return type even void with a constructor it is constructor. But when U specify a return type with a constructor it is no longer constructor it is just a memeber function of that class having duplicate name as constructor.
Did U understood? Hop U will get . By then tack care pls

[surbhigupta gupta]

yes it will not remain any more as constructor if we write the void type before it , because a constructor is having a class name with no return type specified , other wise it will become a method

[Amol Katyare]

It is possible to have a method with the same name as constructor because JVM uses different name spaces for methods and constructor. The one with return type is considered as method.

[Jeff Albertson]

You can even do the following.

public class X {
    X() {}
 
    void X() {
        System.out.println("Hello, World!");
    }
 
    static X X = new X();
}
 
public class Y {
   public static void main(String[] args) {
       X.X.X();
   }
}

I don't know if it's possible to add package X to this