Efficent way to parse XML Data

[YuenLian Wu]

Hi All,

I am not too familiar with DOM API. Currently I have the following XML File,

 
<services>
- <service>
  <name>Currency Conversion Service</name> 
  <wsdl>http://cis.unisa.edu.au/~cisrkt/ect/currency.wsdl</wsdl> 
  </service>
- <service>
  <name>Stock Quote Service</name> 
  <wsdl>http://cis.unisa.edu.au/~cisrkt/ect/stock.wsdl</wsdl> 
  </service>
- <service>
  <name>Another CC Service</name> 
  <wsdl>http://cis.unisa.edu.au/~cisrkt/ect/currency.wsdl</wsdl> 
  </service>
</services>

And My Java Code to parse it will be:

Document doc = parseRemoteXMLFile(path);

NodeList nl = doc.getElementsByTagName("service");

HashMap configMap = new HashMap();
String key = null;
String value = null;

for ( int i = 0; i < nl.getLength(); i++ ) {
key = nl.item(i).getChildNodes().item(1).getChildNodes().item(0).getNodeValue();
value = nl.item(i).getChildNodes().item(3).getChildNodes().item(0).getNodeValue();
configMap.put(key, value);
}  

My Code seems not too efficient as it's kind of hard code.
My ideal wish will be getting values dynamically, please teach me how


Myriads of Thanks


Transistor

[ January 11, 2008: Message edited by: YuenLian Wu ]
[ January 11, 2008: Message edited by: YuenLian Wu ]

[Ulf Dittmer]

You might check out XPath. It allows you to retrieve specific nodes from a DOM tree without having to write the code to work your way through the tree. Plus, you can keep the XPath expression as a string in a config file, thus making the code a bit more independent of the XML structure.

[Bert Bates]

intermediate bound...

[Lukasz Bajzel]

We would suggest you to look at an open source API - JDOM. JDOM is an XML parsing API exclusively for Java. It uses DOM API to parse XML files and make the parsed data availabe as Java objects. It can be downloaded from jdom.org. Most the questions are answered in their tutorial, but if you need any help, let us know.


Hope this helps!

Sincerly,
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