Wrapper Class test : Long Class

[vadiraj vd]

Hi All,
Could anyone explain why NumberFormatException is thrown in the
code below?
CODE
------
<pre>

public class WrapperTest
{
public static void main(String a[])
{
Long l1 = new Long("10L"); // NumberFormatException.
Long l2 = new Long("10l"); // NumberFormatException.
Float f = new Float("10.3f"); // OK.
}
}

</pre>
------------------
Regards
---------
vadiraj

*****************
There's a lot of I in J.
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[Anil Vupputuri]

Fine.As in wrapper class of long i.e., Long(String s) definitely
takes string as a parameter which is parsed into long with valueOf() which returns a new long object initialized to the value of the specified String. Throws an exception if the String cannot be parsed as a long. The radix is assumed to be 10.
so it cant take any extension character like "l" or "L".
where in Float, doesnt consider radix in valueOf() while parsing.
so u can try out in the following way.

public class WrapperTest{
public static void main(String a[]){
long L1=10L;
String L2="10";
Long l1 = new Long(L1);
Long l2 = new Long(L2);
Float f = new Float("10.3f");
}
}
Hope it helps..
Anil.

[Kalidas Pavi]

Wrapper class Long(string s) wraps a primitive long value represented by the string in decimal form. The String s is converted to the long value by calling the method ParseLong(String, radix) with radix 10 so that it converts the string to signed long with base 10.
ParseLong throws a number format exception if any character of the string after the first is not a digit of the specified radix.
wrapper class Long in turn throws a NumberFormatException since the string is not a parsable long integer. This is why you are getting two NumberFormatException 's while you execute the code.
Kalidas.