Changing a double to an int

[ione walker]

Hi,
Thank You all for the help that you give.
I have a variable that I will call OccourancePerLine.
This value is calculated as a double.
1 / How can I truncate it to a integer?
ie OccourancePerLine = 5.6
I want IntOccourancePerLine = 5
2 / How can I get the value rounded to an Integer?
ie OccourancePerLine = 5.6
I want IntOccourancePerLine = 6

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Ione Walker
[e-mail]
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[Art Metzer]

Hi, Ione.
To truncate, simply do a cast:

<font size="2.0">
int i;
double d = 5.6;
i = (int) d;

To round, use the java.lang.Math class:

<font size="2.0">
int i;
double d = 5.6;
i = (int) ( Math.round( d ) );

Here, you need to cast because if you input a double to Math.round(), the result is a long, and to fit it into an int, you have to downcast.
Art

[ione walker]

Yet again you guys & gals
are a HUGE help.

Originally posted by Art Metzer:
[B]Hi, Ione.
To truncate, simply do a cast:

<font size="2.0">
int i;
double d = 5.6;
i = (int) d;

To round, use the java.lang.Math class:

<font size="2.0">
int i;
double d = 5.6;
i = (int) ( Math.round( d ) );

Here, you need to cast because if you input a double to Math.round(), the result is a long, and to fit it into an int, you have to downcast.
Art[/B]

[Greg Harris]

OccurancePerLine sounds familiar... you can also calculate the value as an int from the start:
int occurancePerLine = someString.length % lineLength;
that will give you the whole number integer value that relates to how many times the "string" will fit on the line.
[This message has been edited by Greg Harris (edited May 04, 2001).]

[Ravindra Mohan]

Hi Folks,
Just thought that you all could alternatively use
the <code> Math.ceil(5.6) </code> to covert the double to int.
Cheers,
Ravindra Mohan