A simple Query

[Varun Khanna]

Can anybody explain me the logic behind the output of this code...!!!
public class Test{
public static void main(String args[]){
int i = 0;
i = i++;
System.out.println(i);
}
}

[Sean MacLean]

"varun"
Thank you for your participation here at the Ranch. However, your name doesn't follow the JavaRanch guidelines. Please take a moment and change your "Publicly Displayed Name" by modifying your profile after reviewing the guidelines at http://www.javaranch.com/name.jsp

Thanks.
Sean

[Sean MacLean]

This questions seems better suited to Java In General (Beginner) so I'm moving it there.
Sean

[Bosun Bello]

The out put of this code will be 0. Because the increment is done after the assignment.

[frank davis]

Originally posted by Bosun Bello:
The out put of this code will be 0. Because the increment is done after the assignment.

More interesting is the question of why i never actually gets incremented below :
public class Test{
public static void main(String args[]){
int i = 0;
i = i++;
i = i++;
System.out.println(i);
}
}

[Ilja Preuss]

It gets incremented, but you are overwriting its value afterwards.
You are assigning i the value of an expression. To do this, the expression *first* gets evaluated.
So, i gets incremented - the value of i++ is the value of i before the increment.
Now that the expression has been evaluated, we can assign the result of the evaluation to i. So we are assigning the value of i before the increment to i.
It looks like the incrementation never happend, but it has.
Does that help?