Beginner's classpath problem (I hope...)

[Joel Cochran]

I've been programming in Java for quite a while now but I am now frustrated to no end:
1. I have a Windows XP machine.
2. I have the 1.4.1 SDK installed in directory c:\j2sdk1.4.1
3. I have JAVA_HOME set to c:\j2sdk1.4.1
4 I have a CLASSPATH environment variable set to .;%JAVA_HOME%;%JAVA_HOME%\bin;%JAVA_HOME%\lib\classes.zip;
I can run code using the 'java' command, but when I try to compile something with 'javac' I get the following error:
'javac' is not recognized as an internal or external command, operable program, or batch fie.
Why can't it find javac.exe (which is in the same directoryas java.exe???

Help!
Frustrated in Virginia,
joel

[Barry Gaunt]

I would say first junk the CLASSPATH, you do not need it (yet).
Then add %JAVA_HOME%\bin to the front of your PATH variable.
Try it.
-Barry

[Scott Stevens]

Hi Joel
Check the environment variables via control panel and make sure that javac.exe is located in your path. Sometimes this wont work (we use WinNT4 where I am, and it never seems to acknowledge the change) so as a backup create a batch file that reads
path=<your java home directory>\javac.exe
The other thing you might want to look at is textpad, which has a 'compile java' option build into the tools menu, its the best environment i have worked in or java development
Cheers
Scott Stevens, Analyst/Programmer
Dept. For Courts
Wellington (Of LOTR fame )
New Zealand

[Marilyn de Queiroz]

Remember that PATH is for compiling and CLASSPATH is for running.