• Post Reply
  • Bookmark Topic Watch Topic
  • New Topic

rounding a number (ceiling)?

 
mark babcock
Greenhorn
Posts: 14
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
I'm trying to round an integer.
lets say I have:
x = 22;
y = (x/10);
y would return 2.2 I want it to round up to the next whole number no matter what the decimal value. I was looking for a ceiling function. But, can't seem to find anything that does this.
 
Greg Charles
Sheriff
Posts: 2993
12
Firefox Browser IntelliJ IDE Java Mac Ruby
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
Math.ceil(num)
This takes a double argument and returns a double, though the return value will be equal to an integer, so you can just cast it.
Remember integer division will trucate to an integer, e.g.,

will print out 0. You may want to make x a double, or cast it to double before dividing.
 
  • Post Reply
  • Bookmark Topic Watch Topic
  • New Topic