Win a copy of Programmer's Guide to Java SE 8 Oracle Certified Associate (OCA) this week in the OCAJP forum!
  • Post Reply
  • Bookmark Topic Watch Topic
  • New Topic

Declaration

 
N Nanda
Ranch Hand
Posts: 62
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
Hi all... I am declaring an integer like:
int i=012;
When I am printing this value of i, it is printing 10. Why so ?
 
kelvin cheung
Ranch Hand
Posts: 120
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
because the 0 is meaningless in this case.
it will work if you declare as STRING ...
well actually not so sure
 
fred rosenberger
lowercase baba
Bartender
Posts: 12185
34
Chrome Java Linux
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
When you declare an integer, and the leading digit is a '0', the compiler considers the value to be an Octal representation of the number. So, in your case, it is reading in 12 base 8.
When you print it out, it converts it to decimal. so you get 1*8 + 2*1 or 10.
 
Davy Kelly
Ranch Hand
Posts: 384
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
you can tell octal numbers because they have the preceding 0
so in your case:
int i = 012;
this is how it is represented:
the 0 tells you its octal,
the 1 tells you how many 8's there are, in this case only one,
the 2 tells you how many 1's there are, in this case 2,
so (8*1) + (1*2)= 10
hope this helps.
Davy
 
  • Post Reply
  • Bookmark Topic Watch Topic
  • New Topic